λ^k = 5^3 = 125
Por lo tanto, la probabilidad de que lleguen más de 4 clientes en una hora determinada es: ejercicios resueltos de distribucion de poisson
e^(-λ) = e^(-5) ≈ 0,0067
La probabilidad de que reciban entre 8 y 12 llamadas es: λ^k = 5^3 = 125 Por lo tanto,
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